What are the solutions to the equation 7x^2-3x+j=0 ?

The solutions to the equation 7x^2-3x+j=0 are x=(3+sqrt(9-28j))/(14),x=(3-sqrt(9-28j))/(14)

Find the zeros of 7x^2-3x+j=0

The zeros of 7x^2-3x+j=0 are x=(3+sqrt(9-28j))/(14),x=(3-sqrt(9-28j))/(14)

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7 x^{2} - 3 x + j = 0

x = \frac{3 + 9 - 28 j}{14}, x = \frac{3 - 9 - 28 j}{14}

Solution steps

7 x^{2} - 3 x + j = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 7 j}{2 \cdot 7}

Simplify

(- 3)^{2} - 4 \cdot 7 j : 9 - 28 j

x_{1, 2} = \frac{- ( - 3 ) \pm 9 - 28 j}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 9 - 28 j}{2 \cdot 7}, x_{2} = \frac{- ( - 3 ) - 9 - 28 j}{2 \cdot 7}

x = \frac{- ( - 3 ) + 9 - 28 j}{2 \cdot 7} : \frac{3 + 9 - 28 j}{14}

x = \frac{- ( - 3 ) - 9 - 28 j}{2 \cdot 7} : \frac{3 - 9 - 28 j}{14}

The solutions to the quadratic equation are:

x = \frac{3 + 9 - 28 j}{14}, x = \frac{3 - 9 - 28 j}{14}

z^{2} - 10 z = - 5

3 t^{2} - 21 t + 30 = 0

x^{2} = - 240 - 8 x

F = \frac{m v ^{2}}{2}

2 x^{2} + 2 x + 12 = 0

What are the solutions to the equation 7x^2-3x+j=0 ?
The solutions to the equation 7x^2-3x+j=0 are x=(3+sqrt(9-28j))/(14),x=(3-sqrt(9-28j))/(14)
Find the zeros of 7x^2-3x+j=0
The zeros of 7x^2-3x+j=0 are x=(3+sqrt(9-28j))/(14),x=(3-sqrt(9-28j))/(14)