What are the solutions to the equation x^2=-240-8x ?

The solutions to the equation x^2=-240-8x are x=-4+4sqrt(14)i,x=-4-4sqrt(14)i

Find the zeros of x^2=-240-8x

The zeros of x^2=-240-8x are x=-4+4sqrt(14)i,x=-4-4sqrt(14)i

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x^{2} = - 240 - 8 x

x = - 4 + 414 i, x = - 4 - 414 i

Solution steps

x^{2} = - 240 - 8 x

Move

8 x

to the left side

x^{2} + 8 x = - 240

Move

240

to the left side

x^{2} + 8 x + 240 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 240}{2 \cdot 1}

Simplify

8^{2} - 4 \cdot 1 \cdot 240 : 814 i

x_{1, 2} = \frac{- 8 \pm 8 14 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 8 14 i}{2 \cdot 1}, x_{2} = \frac{- 8 - 8 14 i}{2 \cdot 1}

x = \frac{- 8 + 8 14 i}{2 \cdot 1} : - 4 + 414 i

x = \frac{- 8 - 8 14 i}{2 \cdot 1} : - 4 - 414 i

The solutions to the quadratic equation are:

x = - 4 + 414 i, x = - 4 - 414 i

F = \frac{m v ^{2}}{2}

2 x^{2} + 2 x + 12 = 0

t^{2} + 2 t + 10 = 0

2 x^{2} + 10 x = - 12

6 x^{2} - 48 = - 12 x

What are the solutions to the equation x^2=-240-8x ?
The solutions to the equation x^2=-240-8x are x=-4+4sqrt(14)i,x=-4-4sqrt(14)i
Find the zeros of x^2=-240-8x
The zeros of x^2=-240-8x are x=-4+4sqrt(14)i,x=-4-4sqrt(14)i