What are the solutions to the equation 2x^2-14=27x ?

The solutions to the equation 2x^2-14=27x are x=14,x=-1/2

Find the zeros of 2x^2-14=27x

The zeros of 2x^2-14=27x are x=14,x=-1/2

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2 x^{2} - 14 = 27 x

x = 14, x = - \frac{1}{2}

Decimal Notation

x = 14, x = - 0.5

Solution steps

2 x^{2} - 14 = 27 x

Move

27 x

to the left side

2 x^{2} - 14 - 27 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 27 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 27 ) \pm ( - 27 ) ^{2} - 4 \cdot 2 ( - 14 )}{2 \cdot 2}

(- 27)^{2} - 4 \cdot 2 (- 14) = 29

x_{1, 2} = \frac{- ( - 27 ) \pm 29}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 27 ) + 29}{2 \cdot 2}, x_{2} = \frac{- ( - 27 ) - 29}{2 \cdot 2}

x = \frac{- ( - 27 ) + 29}{2 \cdot 2} : 14

x = \frac{- ( - 27 ) - 29}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 14, x = - \frac{1}{2}

0 = - 16 t^{2} + 32 t + 28

x, x^{2} - 6 y^{2} = x y

2 x^{2} + 2 x + 10 = 0

3 X^{2} - 24 X + 100 = 60

2 x^{2} + 16 = 12 x

What are the solutions to the equation 2x^2-14=27x ?
The solutions to the equation 2x^2-14=27x are x=14,x=-1/2
Find the zeros of 2x^2-14=27x
The zeros of 2x^2-14=27x are x=14,x=-1/2