What are the solutions to the equation (x^2-3x)/2-5=(x-20)/4 ?

The solutions to the equation (x^2-3x)/2-5=(x-20)/4 are x= 7/2 ,x=0

Find the zeros of (x^2-3x)/2-5=(x-20)/4

The zeros of (x^2-3x)/2-5=(x-20)/4 are x= 7/2 ,x=0

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\frac{x ^{2} - 3 x}{2} - 5 = \frac{x - 20}{4}

x = \frac{7}{2}, x = 0

Decimal Notation

x = 3.5, x = 0

Solution steps

\frac{x ^{2} - 3 x}{2} - 5 = \frac{x - 20}{4}

Find Least Common Multiplier of

2, 4 : 4

Multiply by LCM=

4

\frac{x ^{2} - 3 x}{2} \cdot 4 - 5 \cdot 4 = \frac{x - 20}{4} \cdot 4

Simplify

2 (x^{2} - 3 x) - 20 = x - 20

Expand

2 (x^{2} - 3 x) - 20 : 2 x^{2} - 6 x - 20

2 x^{2} - 6 x - 20 = x - 20

Move

20

to the left side

2 x^{2} - 6 x = x

Move

x

to the left side

2 x^{2} - 7 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 \cdot 0 = 7

x_{1, 2} = \frac{- ( - 7 ) \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 7}{2 \cdot 2}, x_{2} = \frac{- ( - 7 ) - 7}{2 \cdot 2}

x = \frac{- ( - 7 ) + 7}{2 \cdot 2} : \frac{7}{2}

x = \frac{- ( - 7 ) - 7}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = 0

2 x^{2} + 7 x - 9 = - 5

x^{2} + 0.54 x - 0.27 = 0

- x^{2} + 14 x + 74 = 0

3 x^{2} + 5 x = 2

12 - 2 x - 3 x^{2}

What are the solutions to the equation (x^2-3x)/2-5=(x-20)/4 ?
The solutions to the equation (x^2-3x)/2-5=(x-20)/4 are x= 7/2 ,x=0
Find the zeros of (x^2-3x)/2-5=(x-20)/4
The zeros of (x^2-3x)/2-5=(x-20)/4 are x= 7/2 ,x=0