What are the solutions to the equation 2x^2+7x-9=-5 ?

The solutions to the equation 2x^2+7x-9=-5 are x= 1/2 ,x=-4

Find the zeros of 2x^2+7x-9=-5

The zeros of 2x^2+7x-9=-5 are x= 1/2 ,x=-4

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2 x^{2} + 7 x - 9 = - 5

x = \frac{1}{2}, x = - 4

Decimal Notation

x = 0.5, x = - 4

Solution steps

2 x^{2} + 7 x - 9 = - 5

Move

5

to the left side

2 x^{2} + 7 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

7^{2} - 4 \cdot 2 (- 4) = 9

x_{1, 2} = \frac{- 7 \pm 9}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 7 + 9}{2 \cdot 2}, x_{2} = \frac{- 7 - 9}{2 \cdot 2}

x = \frac{- 7 + 9}{2 \cdot 2} : \frac{1}{2}

x = \frac{- 7 - 9}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 4

x^{2} + 0.54 x - 0.27 = 0

- x^{2} + 14 x + 74 = 0

3 x^{2} + 5 x = 2

12 - 2 x - 3 x^{2}

b^{2} = 11 b

What are the solutions to the equation 2x^2+7x-9=-5 ?
The solutions to the equation 2x^2+7x-9=-5 are x= 1/2 ,x=-4
Find the zeros of 2x^2+7x-9=-5
The zeros of 2x^2+7x-9=-5 are x= 1/2 ,x=-4