What are the solutions to the equation b^2=11b ?

The solutions to the equation b^2=11b are b=11,b=0

Find the zeros of b^2=11b

The zeros of b^2=11b are b=11,b=0

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b^{2} = 11 b

b = 11, b = 0

Solution steps

b^{2} = 11 b

Move

11 b

to the left side

b^{2} - 11 b = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot 0 = 11

b_{1, 2} = \frac{- ( - 11 ) \pm 11}{2 \cdot 1}

Separate the solutions

b_{1} = \frac{- ( - 11 ) + 11}{2 \cdot 1}, b_{2} = \frac{- ( - 11 ) - 11}{2 \cdot 1}

b = \frac{- ( - 11 ) + 11}{2 \cdot 1} : 11

b = \frac{- ( - 11 ) - 11}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

b = 11, b = 0

0 = 3 x^{2} + 2 x - 2

4 x^{2} - 13 + 3 = 0

6 x^{2} + 4 x - 12 = 0

e = \frac{1}{2} m v^{2}

x, \frac{x ^{2}}{4} + y^{2} + \frac{z ^{2}}{9} = 3

What are the solutions to the equation b^2=11b ?
The solutions to the equation b^2=11b are b=11,b=0
Find the zeros of b^2=11b
The zeros of b^2=11b are b=11,b=0