What are the solutions to the equation -(x^2+4)=0 ?

The solutions to the equation -(x^2+4)=0 are x=2i,x=-2i

Find the zeros of -(x^2+4)=0

The zeros of -(x^2+4)=0 are x=2i,x=-2i

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- (x^{2} + 4) = 0

x = 2 i, x = - 2 i

Solution steps

- (x^{2} + 4) = 0

Divide both sides by

- 1

x^{2} + 4 = 0

Move

4

to the right side

x^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 4, x = - - 4

- 4 = 2 i

- - 4 = - 2 i

x = 2 i, x = - 2 i

4 u^{2} - 28 u = 0

k, x = \frac{1}{2} (k^{2} - 1)

x^{2} - 9 x + 3

x^{2} - 10 x + 24 = 0

24 x^{2} - 72 x + 48 = 0

What are the solutions to the equation -(x^2+4)=0 ?
The solutions to the equation -(x^2+4)=0 are x=2i,x=-2i
Find the zeros of -(x^2+4)=0
The zeros of -(x^2+4)=0 are x=2i,x=-2i