What are the solutions to the equation 3x^2+4=-7x ?

The solutions to the equation 3x^2+4=-7x are x=-1,x=-4/3

Find the zeros of 3x^2+4=-7x

The zeros of 3x^2+4=-7x are x=-1,x=-4/3

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3 x^{2} + 4 = - 7 x

x = - 1, x = - \frac{4}{3}

Decimal Notation

x = - 1, x = - 1.33333 \dots

Solution steps

3 x^{2} + 4 = - 7 x

Move

7 x

to the left side

3 x^{2} + 4 + 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} + 7 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 3 \cdot 4}{2 \cdot 3}

7^{2} - 4 \cdot 3 \cdot 4 = 1

x_{1, 2} = \frac{- 7 \pm 1}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 7 + 1}{2 \cdot 3}, x_{2} = \frac{- 7 - 1}{2 \cdot 3}

x = \frac{- 7 + 1}{2 \cdot 3} : - 1

x = \frac{- 7 - 1}{2 \cdot 3} : - \frac{4}{3}

The solutions to the quadratic equation are:

x = - 1, x = - \frac{4}{3}

14 x^{2} - 60 x + 50 = 0

(x - 3) (x + 3) = - 5 x

x^{2} - 7 x + 10 = 0

a (x) = - x (x - 80)

2 x^{2} + 20 x + 42 = 0

What are the solutions to the equation 3x^2+4=-7x ?
The solutions to the equation 3x^2+4=-7x are x=-1,x=-4/3
Find the zeros of 3x^2+4=-7x
The zeros of 3x^2+4=-7x are x=-1,x=-4/3