What are the solutions to the equation 4.9x^2-5x-10=0 ?

The solutions to the equation 4.9x^2-5x-10=0 are x=(5(5+sqrt(221)))/(49),x=(5(5-sqrt(221)))/(49)

Find the zeros of 4.9x^2-5x-10=0

The zeros of 4.9x^2-5x-10=0 are x=(5(5+sqrt(221)))/(49),x=(5(5-sqrt(221)))/(49)

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4.9 x^{2} - 5 x - 10 = 0

x = \frac{5 ( 5 + 221 )}{49}, x = \frac{5 ( 5 - 221 )}{49}

Decimal Notation

x = 2.02714 \dots, x = - 1.00674 \dots

Solution steps

4.9 x^{2} - 5 x - 10 = 0

Multiply both sides by

10

49 x^{2} - 50 x - 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 50 ) \pm ( - 50 ) ^{2} - 4 \cdot 49 ( - 100 )}{2 \cdot 49}

(- 50)^{2} - 4 \cdot 49 (- 100) = 10221

x_{1, 2} = \frac{- ( - 50 ) \pm 10 221}{2 \cdot 49}

Separate the solutions

x_{1} = \frac{- ( - 50 ) + 10 221}{2 \cdot 49}, x_{2} = \frac{- ( - 50 ) - 10 221}{2 \cdot 49}

x = \frac{- ( - 50 ) + 10 221}{2 \cdot 49} : \frac{5 ( 5 + 221 )}{49}

x = \frac{- ( - 50 ) - 10 221}{2 \cdot 49} : \frac{5 ( 5 - 221 )}{49}

The solutions to the quadratic equation are:

x = \frac{5 ( 5 + 221 )}{49}, x = \frac{5 ( 5 - 221 )}{49}

z^{2} + 26 z + 37 = 0

s^{2} + 2 s + 100 = 0

x^{2} + 40 x + 4000 = 0

(x + 1)^{2} - 2 = 3 x + 1

- x^{2} - 6 x - 2 = 0

What are the solutions to the equation 4.9x^2-5x-10=0 ?
The solutions to the equation 4.9x^2-5x-10=0 are x=(5(5+sqrt(221)))/(49),x=(5(5-sqrt(221)))/(49)
Find the zeros of 4.9x^2-5x-10=0
The zeros of 4.9x^2-5x-10=0 are x=(5(5+sqrt(221)))/(49),x=(5(5-sqrt(221)))/(49)