What are the solutions to the equation 16x^2-40x+221=0 ?

The solutions to the equation 16x^2-40x+221=0 are x= 5/4+i 7/2 ,x= 5/4-i 7/2

Find the zeros of 16x^2-40x+221=0

The zeros of 16x^2-40x+221=0 are x= 5/4+i 7/2 ,x= 5/4-i 7/2

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16 x^{2} - 40 x + 221 = 0

x = \frac{5}{4} + i \frac{7}{2}, x = \frac{5}{4} - i \frac{7}{2}

Solution steps

16 x^{2} - 40 x + 221 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 16 \cdot 221}{2 \cdot 16}

Simplify

(- 40)^{2} - 4 \cdot 16 \cdot 221 : 112 i

x_{1, 2} = \frac{- ( - 40 ) \pm 112 i}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 112 i}{2 \cdot 16}, x_{2} = \frac{- ( - 40 ) - 112 i}{2 \cdot 16}

x = \frac{- ( - 40 ) + 112 i}{2 \cdot 16} : \frac{5}{4} + i \frac{7}{2}

x = \frac{- ( - 40 ) - 112 i}{2 \cdot 16} : \frac{5}{4} - i \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{5}{4} + i \frac{7}{2}, x = \frac{5}{4} - i \frac{7}{2}

t^{2} = - 11

7 x^{2} - 3 x - 3 = 0

x^{2} = 30 - 7 x

X^{2} = 5 X

15 x^{2} + 13 x - 6 = 0

What are the solutions to the equation 16x^2-40x+221=0 ?
The solutions to the equation 16x^2-40x+221=0 are x= 5/4+i 7/2 ,x= 5/4-i 7/2
Find the zeros of 16x^2-40x+221=0
The zeros of 16x^2-40x+221=0 are x= 5/4+i 7/2 ,x= 5/4-i 7/2