What are the solutions to the equation 7x^2-3x-3=0 ?

The solutions to the equation 7x^2-3x-3=0 are x=(3+sqrt(93))/(14),x=(3-sqrt(93))/(14)

Find the zeros of 7x^2-3x-3=0

The zeros of 7x^2-3x-3=0 are x=(3+sqrt(93))/(14),x=(3-sqrt(93))/(14)

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7 x^{2} - 3 x - 3 = 0

x = \frac{3 + 93}{14}, x = \frac{3 - 93}{14}

Decimal Notation

x = 0.90311 \dots, x = - 0.47454 \dots

Solution steps

7 x^{2} - 3 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 7 ( - 3 )}{2 \cdot 7}

(- 3)^{2} - 4 \cdot 7 (- 3) = 93

x_{1, 2} = \frac{- ( - 3 ) \pm 93}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 93}{2 \cdot 7}, x_{2} = \frac{- ( - 3 ) - 93}{2 \cdot 7}

x = \frac{- ( - 3 ) + 93}{2 \cdot 7} : \frac{3 + 93}{14}

x = \frac{- ( - 3 ) - 93}{2 \cdot 7} : \frac{3 - 93}{14}

The solutions to the quadratic equation are:

x = \frac{3 + 93}{14}, x = \frac{3 - 93}{14}

x^{2} = 30 - 7 x

X^{2} = 5 X

15 x^{2} + 13 x - 6 = 0

m^{2} + 3 m - 1 = 0

10 v^{2} = 13 v + 3

What are the solutions to the equation 7x^2-3x-3=0 ?
The solutions to the equation 7x^2-3x-3=0 are x=(3+sqrt(93))/(14),x=(3-sqrt(93))/(14)
Find the zeros of 7x^2-3x-3=0
The zeros of 7x^2-3x-3=0 are x=(3+sqrt(93))/(14),x=(3-sqrt(93))/(14)