What are the solutions to the equation m^2+3m-1=0 ?

The solutions to the equation m^2+3m-1=0 are m=(-3+sqrt(13))/2 ,m=(-3-sqrt(13))/2

Find the zeros of m^2+3m-1=0

The zeros of m^2+3m-1=0 are m=(-3+sqrt(13))/2 ,m=(-3-sqrt(13))/2

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m^{2} + 3 m - 1 = 0

m = \frac{- 3 + 13}{2}, m = \frac{- 3 - 13}{2}

Decimal Notation

m = 0.30277 \dots, m = - 3.30277 \dots

Solution steps

m^{2} + 3 m - 1 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 1) = 13

m_{1, 2} = \frac{- 3 \pm 13}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 3 + 13}{2 \cdot 1}, m_{2} = \frac{- 3 - 13}{2 \cdot 1}

m = \frac{- 3 + 13}{2 \cdot 1} : \frac{- 3 + 13}{2}

m = \frac{- 3 - 13}{2 \cdot 1} : \frac{- 3 - 13}{2}

The solutions to the quadratic equation are:

m = \frac{- 3 + 13}{2}, m = \frac{- 3 - 13}{2}

10 v^{2} = 13 v + 3

x^{2} + x + \frac{5}{4} = 0

x^{2} = 2^{2} + (23)^{2}

x^{2} + 2 x + 4 = 0

2 y^{2} - 3 y - 2 = 0

What are the solutions to the equation m^2+3m-1=0 ?
The solutions to the equation m^2+3m-1=0 are m=(-3+sqrt(13))/2 ,m=(-3-sqrt(13))/2
Find the zeros of m^2+3m-1=0
The zeros of m^2+3m-1=0 are m=(-3+sqrt(13))/2 ,m=(-3-sqrt(13))/2