What are the solutions to the equation x^2+x-99=0 ?

The solutions to the equation x^2+x-99=0 are x=(-1+sqrt(397))/2 ,x=(-1-sqrt(397))/2

Find the zeros of x^2+x-99=0

The zeros of x^2+x-99=0 are x=(-1+sqrt(397))/2 ,x=(-1-sqrt(397))/2

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x^{2} + x - 99 = 0

x = \frac{- 1 + 397}{2}, x = \frac{- 1 - 397}{2}

Decimal Notation

x = 9.46242 \dots, x = - 10.46242 \dots

Solution steps

x^{2} + x - 99 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 99 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 99) = 397

x_{1, 2} = \frac{- 1 \pm 397}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 397}{2 \cdot 1}, x_{2} = \frac{- 1 - 397}{2 \cdot 1}

x = \frac{- 1 + 397}{2 \cdot 1} : \frac{- 1 + 397}{2}

x = \frac{- 1 - 397}{2 \cdot 1} : \frac{- 1 - 397}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 397}{2}, x = \frac{- 1 - 397}{2}

p^{2} + 5 = 6 p

x^{2} + 10 x + 16 = 0

r, r^{2} = \frac{1}{θ}

x^{2} - 6.5 x - 1.5

0 = - 0.525 x^{2} + 2.1 x + 1.9

What are the solutions to the equation x^2+x-99=0 ?
The solutions to the equation x^2+x-99=0 are x=(-1+sqrt(397))/2 ,x=(-1-sqrt(397))/2
Find the zeros of x^2+x-99=0
The zeros of x^2+x-99=0 are x=(-1+sqrt(397))/2 ,x=(-1-sqrt(397))/2