What are the solutions to the equation p^2+5=6p ?

The solutions to the equation p^2+5=6p are p=5,p=1

Find the zeros of p^2+5=6p

The zeros of p^2+5=6p are p=5,p=1

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p^{2} + 5 = 6 p

p = 5, p = 1

Solution steps

p^{2} + 5 = 6 p

Move

6 p

to the left side

p^{2} + 5 - 6 p = 0

Write in the standard form

a x^{2} + b x + c = 0

p^{2} - 6 p + 5 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 5 = 4

p_{1, 2} = \frac{- ( - 6 ) \pm 4}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 6 ) + 4}{2 \cdot 1}, p_{2} = \frac{- ( - 6 ) - 4}{2 \cdot 1}

p = \frac{- ( - 6 ) + 4}{2 \cdot 1} : 5

p = \frac{- ( - 6 ) - 4}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

p = 5, p = 1

x^{2} + 10 x + 16 = 0

r, r^{2} = \frac{1}{θ}

x^{2} - 6.5 x - 1.5

0 = - 0.525 x^{2} + 2.1 x + 1.9

12 x^{2} - 16 x = 0

What are the solutions to the equation p^2+5=6p ?
The solutions to the equation p^2+5=6p are p=5,p=1
Find the zeros of p^2+5=6p
The zeros of p^2+5=6p are p=5,p=1