What are the solutions to the equation x^2-10x=-9x-1 ?

The solutions to the equation x^2-10x=-9x-1 are x= 1/2+i(sqrt(3))/2 ,x= 1/2-i(sqrt(3))/2

Find the zeros of x^2-10x=-9x-1

The zeros of x^2-10x=-9x-1 are x= 1/2+i(sqrt(3))/2 ,x= 1/2-i(sqrt(3))/2

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x^{2} - 10 x = - 9 x - 1

x = \frac{1}{2} + i \frac{3}{2}, x = \frac{1}{2} - i \frac{3}{2}

Solution steps

x^{2} - 10 x = - 9 x - 1

Move

1

to the left side

x^{2} - 10 x + 1 = - 9 x

Move

9 x

to the left side

x^{2} - x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

Simplify

(- 1)^{2} - 4 \cdot 1 \cdot 1 : 3 i

x_{1, 2} = \frac{- ( - 1 ) \pm 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 3 i}{2 \cdot 1}

x = \frac{- ( - 1 ) + 3 i}{2 \cdot 1} : \frac{1}{2} + i \frac{3}{2}

x = \frac{- ( - 1 ) - 3 i}{2 \cdot 1} : \frac{1}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{3}{2}, x = \frac{1}{2} - i \frac{3}{2}

(x + 6) x = 720

x^{2} + 18 x = 15

d = 0.006 (1 - \frac{( ( 1.82 ) - ( d ) ( 1500 ) )}{- 3})^{2}

0 = a (x - 3)^{2} + 1

6 x^{2} + 5 x - 1

What are the solutions to the equation x^2-10x=-9x-1 ?
The solutions to the equation x^2-10x=-9x-1 are x= 1/2+i(sqrt(3))/2 ,x= 1/2-i(sqrt(3))/2
Find the zeros of x^2-10x=-9x-1
The zeros of x^2-10x=-9x-1 are x= 1/2+i(sqrt(3))/2 ,x= 1/2-i(sqrt(3))/2