What are the solutions to the equation 3x^2-2x=2x+7 ?

The solutions to the equation 3x^2-2x=2x+7 are x= 7/3 ,x=-1

Find the zeros of 3x^2-2x=2x+7

The zeros of 3x^2-2x=2x+7 are x= 7/3 ,x=-1

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3 x^{2} - 2 x = 2 x + 7

x = \frac{7}{3}, x = - 1

Decimal Notation

x = 2.33333 \dots, x = - 1

Solution steps

3 x^{2} - 2 x = 2 x + 7

Move

7

to the left side

3 x^{2} - 2 x - 7 = 2 x

Move

2 x

to the left side

3 x^{2} - 4 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

(- 4)^{2} - 4 \cdot 3 (- 7) = 10

x_{1, 2} = \frac{- ( - 4 ) \pm 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 10}{2 \cdot 3}, x_{2} = \frac{- ( - 4 ) - 10}{2 \cdot 3}

x = \frac{- ( - 4 ) + 10}{2 \cdot 3} : \frac{7}{3}

x = \frac{- ( - 4 ) - 10}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

x = \frac{7}{3}, x = - 1

x^{2} - 5 x - 15 = 0

a, (a + b) (a - b) = b (a - b)

A (y) = 240 y - 2 y^{2}

x, 2 k x^{2} + 3 x - 8 = 0

3 x^{2} - 20 x + 50 = x^{2} - 10 x + 50

What are the solutions to the equation 3x^2-2x=2x+7 ?
The solutions to the equation 3x^2-2x=2x+7 are x= 7/3 ,x=-1
Find the zeros of 3x^2-2x=2x+7
The zeros of 3x^2-2x=2x+7 are x= 7/3 ,x=-1