What are the solutions to the equation 3x^2-20x+50=x^2-10x+50 ?

The solutions to the equation 3x^2-20x+50=x^2-10x+50 are x=5,x=0

Find the zeros of 3x^2-20x+50=x^2-10x+50

The zeros of 3x^2-20x+50=x^2-10x+50 are x=5,x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} - 20 x + 50 = x^{2} - 10 x + 50

x = 5, x = 0

Solution steps

3 x^{2} - 20 x + 50 = x^{2} - 10 x + 50

Move

50

to the left side

3 x^{2} - 20 x = x^{2} - 10 x

Move

10 x

to the left side

3 x^{2} - 10 x = x^{2}

Move

x^{2}

to the left side

2 x^{2} - 10 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 10)^{2} - 4 \cdot 2 \cdot 0 = 10

x_{1, 2} = \frac{- ( - 10 ) \pm 10}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 10}{2 \cdot 2}, x_{2} = \frac{- ( - 10 ) - 10}{2 \cdot 2}

x = \frac{- ( - 10 ) + 10}{2 \cdot 2} : 5

x = \frac{- ( - 10 ) - 10}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

x = 5, x = 0

2 x^{2} - 5 x

(- x + 1)^{2} = 0

x^{2} = 3^{2} + 6^{2}

2 x^{2} + 2 x - 1 = x^{2} + 6 x - 5

p, (y - p x)^{2} = 1 + p^{2}

What are the solutions to the equation 3x^2-20x+50=x^2-10x+50 ?
The solutions to the equation 3x^2-20x+50=x^2-10x+50 are x=5,x=0
Find the zeros of 3x^2-20x+50=x^2-10x+50
The zeros of 3x^2-20x+50=x^2-10x+50 are x=5,x=0