What are the solutions to the equation (-x+1)^2=0 ?

The solutions to the equation (-x+1)^2=0 are x=1

Find the zeros of (-x+1)^2=0

The zeros of (-x+1)^2=0 are x=1

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(- x + 1)^{2} = 0

x = 1

Solution steps

(- x + 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

- x + 1 = 0 : x = 1

The solution to the quadratic equation is:

x = 1

x^{2} = 3^{2} + 6^{2}

2 x^{2} + 2 x - 1 = x^{2} + 6 x - 5

p, (y - p x)^{2} = 1 + p^{2}

x, A = (x + y) (x + y)

x, x^{2} + y^{2} - 4 x - 2 y + 7 = 0

What are the solutions to the equation (-x+1)^2=0 ?
The solutions to the equation (-x+1)^2=0 are x=1
Find the zeros of (-x+1)^2=0
The zeros of (-x+1)^2=0 are x=1