What are the solutions to the equation 15^2+12^2=c^2 ?

The solutions to the equation 15^2+12^2=c^2 are c=3sqrt(41),c=-3sqrt(41)

Find the zeros of 15^2+12^2=c^2

The zeros of 15^2+12^2=c^2 are c=3sqrt(41),c=-3sqrt(41)

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1 5^{2} + 1 2^{2} = c^{2}

c = 341, c = - 341

Decimal

c = 19.20937 \dots, c = - 19.20937 \dots

Solution steps

1 5^{2} + 1 2^{2} = c^{2}

Switch sides

c^{2} = 1 5^{2} + 1 2^{2}

Simplify

1 5^{2} + 1 2^{2} : 369

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 369, c = - 369

369 = 341

- 369 = - 341

c = 341, c = - 341

(X + 3)^{2} - 13 = - 4

r^{2} + 2 r + \frac{5}{4} = 0

x^{2} + 5 x = 2 x^{2}

6 x^{2} + 19 x - 20 = 0

9 b^{2} + 6 b = - 1

What are the solutions to the equation 15^2+12^2=c^2 ?
The solutions to the equation 15^2+12^2=c^2 are c=3sqrt(41),c=-3sqrt(41)
Find the zeros of 15^2+12^2=c^2
The zeros of 15^2+12^2=c^2 are c=3sqrt(41),c=-3sqrt(41)