What are the solutions to the equation (2sqrt(13))^2+y^2=13^2 ?

The solutions to the equation (2sqrt(13))^2+y^2=13^2 are y=3sqrt(13),y=-3sqrt(13)

Find the zeros of (2sqrt(13))^2+y^2=13^2

The zeros of (2sqrt(13))^2+y^2=13^2 are y=3sqrt(13),y=-3sqrt(13)

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(213)^{2} + y^{2} = 1 3^{2}

y = 313, y = - 313

Decimal

y = 10.81665 \dots, y = - 10.81665 \dots

Solution steps

(213)^{2} + y^{2} = 1 3^{2}

Expand

(213)^{2} + y^{2} : 52 + y^{2}

Expand

1 3^{2} : 169

52 + y^{2} = 169

Move

52

to the right side

y^{2} = 117

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 117, y = - 117

117 = 313

- 117 = - 313

y = 313, y = - 313

x, x^{2} + x y + 4 y^{2} = 6

12 x^{2} = 5 + 10 x

k (x) = - x^{2} - 3, k (1)

9 a^{2} + a + 4 = 0

x^{2} - 12 x + 40

What are the solutions to the equation (2sqrt(13))^2+y^2=13^2 ?
The solutions to the equation (2sqrt(13))^2+y^2=13^2 are y=3sqrt(13),y=-3sqrt(13)
Find the zeros of (2sqrt(13))^2+y^2=13^2
The zeros of (2sqrt(13))^2+y^2=13^2 are y=3sqrt(13),y=-3sqrt(13)