What are the solutions to the equation 12x^2=5+10x ?

The solutions to the equation 12x^2=5+10x are x=(5+sqrt(85))/(12),x=(5-sqrt(85))/(12)

Find the zeros of 12x^2=5+10x

The zeros of 12x^2=5+10x are x=(5+sqrt(85))/(12),x=(5-sqrt(85))/(12)

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12 x^{2} = 5 + 10 x

x = \frac{5 + 85}{12}, x = \frac{5 - 85}{12}

Decimal Notation

x = 1.18496 \dots, x = - 0.35162 \dots

Solution steps

12 x^{2} = 5 + 10 x

Move

10 x

to the left side

12 x^{2} - 10 x = 5

Move

5

to the left side

12 x^{2} - 10 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 12 ( - 5 )}{2 \cdot 12}

(- 10)^{2} - 4 \cdot 12 (- 5) = 285

x_{1, 2} = \frac{- ( - 10 ) \pm 2 85}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 85}{2 \cdot 12}, x_{2} = \frac{- ( - 10 ) - 2 85}{2 \cdot 12}

x = \frac{- ( - 10 ) + 2 85}{2 \cdot 12} : \frac{5 + 85}{12}

x = \frac{- ( - 10 ) - 2 85}{2 \cdot 12} : \frac{5 - 85}{12}

The solutions to the quadratic equation are:

x = \frac{5 + 85}{12}, x = \frac{5 - 85}{12}

k (x) = - x^{2} - 3, k (1)

9 a^{2} + a + 4 = 0

x^{2} - 12 x + 40

\frac{x ^{2}}{4} - \frac{9}{16} = 0

3 r^{2} - r - 7 = 0

What are the solutions to the equation 12x^2=5+10x ?
The solutions to the equation 12x^2=5+10x are x=(5+sqrt(85))/(12),x=(5-sqrt(85))/(12)
Find the zeros of 12x^2=5+10x
The zeros of 12x^2=5+10x are x=(5+sqrt(85))/(12),x=(5-sqrt(85))/(12)