What are the solutions to the equation 3r^2-r-7=0 ?

The solutions to the equation 3r^2-r-7=0 are r=(1+sqrt(85))/6 ,r=(1-sqrt(85))/6

Find the zeros of 3r^2-r-7=0

The zeros of 3r^2-r-7=0 are r=(1+sqrt(85))/6 ,r=(1-sqrt(85))/6

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3 r^{2} - r - 7 = 0

r = \frac{1 + 85}{6}, r = \frac{1 - 85}{6}

Decimal Notation

r = 1.70325 \dots, r = - 1.36992 \dots

Solution steps

3 r^{2} - r - 7 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

(- 1)^{2} - 4 \cdot 3 (- 7) = 85

r_{1, 2} = \frac{- ( - 1 ) \pm 85}{2 \cdot 3}

Separate the solutions

r_{1} = \frac{- ( - 1 ) + 85}{2 \cdot 3}, r_{2} = \frac{- ( - 1 ) - 85}{2 \cdot 3}

r = \frac{- ( - 1 ) + 85}{2 \cdot 3} : \frac{1 + 85}{6}

r = \frac{- ( - 1 ) - 85}{2 \cdot 3} : \frac{1 - 85}{6}

The solutions to the quadratic equation are:

r = \frac{1 + 85}{6}, r = \frac{1 - 85}{6}

(2 x - 3)^{2} + (x + 3) (x - 5) = 0

(3 x - 2)^{2} = 18

(3 x - 2)^{2} = 16

A = y^{2} - 40 y

X^{2} + 7 X = - 10

What are the solutions to the equation 3r^2-r-7=0 ?
The solutions to the equation 3r^2-r-7=0 are r=(1+sqrt(85))/6 ,r=(1-sqrt(85))/6
Find the zeros of 3r^2-r-7=0
The zeros of 3r^2-r-7=0 are r=(1+sqrt(85))/6 ,r=(1-sqrt(85))/6