What are the solutions to the equation 3y^2-24y+50=0 ?

The solutions to the equation 3y^2-24y+50=0 are y=4+isqrt(2/3),y=4-isqrt(2/3)

Find the zeros of 3y^2-24y+50=0

The zeros of 3y^2-24y+50=0 are y=4+isqrt(2/3),y=4-isqrt(2/3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 y^{2} - 24 y + 50 = 0

y = 4 + i \frac{2}{3}, y = 4 - i \frac{2}{3}

Solution steps

3 y^{2} - 24 y + 50 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 3 \cdot 50}{2 \cdot 3}

Simplify

(- 24)^{2} - 4 \cdot 3 \cdot 50 : 26 i

y_{1, 2} = \frac{- ( - 24 ) \pm 2 6 i}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- ( - 24 ) + 2 6 i}{2 \cdot 3}, y_{2} = \frac{- ( - 24 ) - 2 6 i}{2 \cdot 3}

y = \frac{- ( - 24 ) + 2 6 i}{2 \cdot 3} : 4 + i \frac{2}{3}

y = \frac{- ( - 24 ) - 2 6 i}{2 \cdot 3} : 4 - i \frac{2}{3}

The solutions to the quadratic equation are:

y = 4 + i \frac{2}{3}, y = 4 - i \frac{2}{3}

2 x^{2} + 5 x - 20 = 0

x^{2} - x - 2 = 0

4 (x - 6)^{2} = 100

(x + 2) (x - 2) = 32

(x + 2)^{2} - 2 (x + 2) - 15 = 0

What are the solutions to the equation 3y^2-24y+50=0 ?
The solutions to the equation 3y^2-24y+50=0 are y=4+isqrt(2/3),y=4-isqrt(2/3)
Find the zeros of 3y^2-24y+50=0
The zeros of 3y^2-24y+50=0 are y=4+isqrt(2/3),y=4-isqrt(2/3)