What are the solutions to the equation x^2-27x+180=-3x-20 ?

The solutions to the equation x^2-27x+180=-3x-20 are x=12+2sqrt(14)i,x=12-2sqrt(14)i

Find the zeros of x^2-27x+180=-3x-20

The zeros of x^2-27x+180=-3x-20 are x=12+2sqrt(14)i,x=12-2sqrt(14)i

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x^{2} - 27 x + 180 = - 3 x - 20

x = 12 + 214 i, x = 12 - 214 i

Solution steps

x^{2} - 27 x + 180 = - 3 x - 20

Move

20

to the left side

x^{2} - 27 x + 200 = - 3 x

Move

3 x

to the left side

x^{2} - 24 x + 200 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 1 \cdot 200}{2 \cdot 1}

Simplify

(- 24)^{2} - 4 \cdot 1 \cdot 200 : 414 i

x_{1, 2} = \frac{- ( - 24 ) \pm 4 14 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 4 14 i}{2 \cdot 1}, x_{2} = \frac{- ( - 24 ) - 4 14 i}{2 \cdot 1}

x = \frac{- ( - 24 ) + 4 14 i}{2 \cdot 1} : 12 + 214 i

x = \frac{- ( - 24 ) - 4 14 i}{2 \cdot 1} : 12 - 214 i

The solutions to the quadratic equation are:

x = 12 + 214 i, x = 12 - 214 i

x (2 x + 7) = 15

3 s^{2} + 10 s + 4 = 0

6 x^{2} = 15 x

9 x^{2} + 18 x - 5 = 0

- 2 x^{2} + 3 x = 1

What are the solutions to the equation x^2-27x+180=-3x-20 ?
The solutions to the equation x^2-27x+180=-3x-20 are x=12+2sqrt(14)i,x=12-2sqrt(14)i
Find the zeros of x^2-27x+180=-3x-20
The zeros of x^2-27x+180=-3x-20 are x=12+2sqrt(14)i,x=12-2sqrt(14)i