What are the solutions to the equation -2x^2+3x=1 ?

The solutions to the equation -2x^2+3x=1 are x= 1/2 ,x=1

Find the zeros of -2x^2+3x=1

The zeros of -2x^2+3x=1 are x= 1/2 ,x=1

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- 2 x^{2} + 3 x = 1

x = \frac{1}{2}, x = 1

Decimal Notation

x = 0.5, x = 1

Solution steps

- 2 x^{2} + 3 x = 1

Move

1

to the left side

- 2 x^{2} + 3 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 2 ) ( - 1 )}{2 ( - 2 )}

3^{2} - 4 (- 2) (- 1) = 1

x_{1, 2} = \frac{- 3 \pm 1}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 3 + 1}{2 ( - 2 )}, x_{2} = \frac{- 3 - 1}{2 ( - 2 )}

x = \frac{- 3 + 1}{2 ( - 2 )} : \frac{1}{2}

x = \frac{- 3 - 1}{2 ( - 2 )} : 1

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = 1

x^{2} - 2 x - 60 = 0

1 = a (2 x^{2} - x) + b (3 x^{2} + 1) + c (x^{2})

3 x^{2} + 10 x + 75 = 2 x^{2} - 7 x + 15

c^{2} - 18 c = - 65

81 x^{2} = 64

What are the solutions to the equation -2x^2+3x=1 ?
The solutions to the equation -2x^2+3x=1 are x= 1/2 ,x=1
Find the zeros of -2x^2+3x=1
The zeros of -2x^2+3x=1 are x= 1/2 ,x=1