What are the solutions to the equation solvefor x,y-ln(y)=x^2+1 ?

The solutions to the equation solvefor x,y-ln(y)=x^2+1 are x=sqrt(y-ln(y)-1),x=-sqrt(y-ln(y)-1)

Find the zeros of solvefor x,y-ln(y)=x^2+1

The zeros of solvefor x,y-ln(y)=x^2+1 are x=sqrt(y-ln(y)-1),x=-sqrt(y-ln(y)-1)

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solve for

x, y - ln (y) = x^{2} + 1

x = y - ln (y) - 1, x = - y - ln (y) - 1

Solution steps

y - ln (y) = x^{2} + 1

Switch sides

x^{2} + 1 = y - ln (y)

Move

1

to the right side

x^{2} = y - ln (y) - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = y - ln (y) - 1, x = - y - ln (y) - 1

4 - 2 x^{2} = 12

14.59 \cdot 0.6 \cdot t - \frac{1}{2} \cdot 5 \cdot t^{2} = 1

y, 4 x^{2} + y^{2} = 4

x^{2} - 20 x + 12 = 0

a^{2} + 14 a - 51 = 0

What are the solutions to the equation solvefor x,y-ln(y)=x^2+1 ?
The solutions to the equation solvefor x,y-ln(y)=x^2+1 are x=sqrt(y-ln(y)-1),x=-sqrt(y-ln(y)-1)
Find the zeros of solvefor x,y-ln(y)=x^2+1
The zeros of solvefor x,y-ln(y)=x^2+1 are x=sqrt(y-ln(y)-1),x=-sqrt(y-ln(y)-1)