What are the solutions to the equation 13x^2-6x-12=4x^2+3x ?

The solutions to the equation 13x^2-6x-12=4x^2+3x are x=(3+sqrt(57))/6 ,x=(3-sqrt(57))/6

Find the zeros of 13x^2-6x-12=4x^2+3x

The zeros of 13x^2-6x-12=4x^2+3x are x=(3+sqrt(57))/6 ,x=(3-sqrt(57))/6

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13 x^{2} - 6 x - 12 = 4 x^{2} + 3 x

x = \frac{3 + 57}{6}, x = \frac{3 - 57}{6}

Decimal Notation

x = 1.75830 \dots, x = - 0.75830 \dots

Solution steps

13 x^{2} - 6 x - 12 = 4 x^{2} + 3 x

Move

3 x

to the left side

13 x^{2} - 9 x - 12 = 4 x^{2}

Move

4 x^{2}

to the left side

9 x^{2} - 9 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 9 ( - 12 )}{2 \cdot 9}

(- 9)^{2} - 4 \cdot 9 (- 12) = 357

x_{1, 2} = \frac{- ( - 9 ) \pm 3 57}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 3 57}{2 \cdot 9}, x_{2} = \frac{- ( - 9 ) - 3 57}{2 \cdot 9}

x = \frac{- ( - 9 ) + 3 57}{2 \cdot 9} : \frac{3 + 57}{6}

x = \frac{- ( - 9 ) - 3 57}{2 \cdot 9} : \frac{3 - 57}{6}

The solutions to the quadratic equation are:

x = \frac{3 + 57}{6}, x = \frac{3 - 57}{6}

w^{2} - 22 w + 2 = 0

x^{2} + 8 x - 17 = 9

x^{2} = \frac{3}{3}

7 + x (x) = 120

(x - 1)^{2} = 2 x - 3

What are the solutions to the equation 13x^2-6x-12=4x^2+3x ?
The solutions to the equation 13x^2-6x-12=4x^2+3x are x=(3+sqrt(57))/6 ,x=(3-sqrt(57))/6
Find the zeros of 13x^2-6x-12=4x^2+3x
The zeros of 13x^2-6x-12=4x^2+3x are x=(3+sqrt(57))/6 ,x=(3-sqrt(57))/6