What are the solutions to the equation 8b^2-1=-78 ?

The solutions to the equation 8b^2-1=-78 are b=(sqrt(77))/(2sqrt(2))i,b=-(sqrt(77))/(2sqrt(2))i

Find the zeros of 8b^2-1=-78

The zeros of 8b^2-1=-78 are b=(sqrt(77))/(2sqrt(2))i,b=-(sqrt(77))/(2sqrt(2))i

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8 b^{2} - 1 = - 78

b = \frac{77}{2 2} i, b = - \frac{77}{2 2} i

Solution steps

8 b^{2} - 1 = - 78

Move

1

to the right side

8 b^{2} = - 77

Divide both sides by

8

b^{2} = - \frac{77}{8}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = - \frac{77}{8}, b = - - \frac{77}{8}

- \frac{77}{8} = \frac{77}{2 2} i

- - \frac{77}{8} = - \frac{77}{2 2} i

b = \frac{77}{2 2} i, b = - \frac{77}{2 2} i

0 = 12 x^{2} - 72 x + 80

y^{2} = 10 y - 16

2 y^{2} - 4 y

w^{2} + 4 w + 3 = 0

x^{2} + 2 x - 7

What are the solutions to the equation 8b^2-1=-78 ?
The solutions to the equation 8b^2-1=-78 are b=(sqrt(77))/(2sqrt(2))i,b=-(sqrt(77))/(2sqrt(2))i
Find the zeros of 8b^2-1=-78
The zeros of 8b^2-1=-78 are b=(sqrt(77))/(2sqrt(2))i,b=-(sqrt(77))/(2sqrt(2))i