What are the solutions to the equation 0=3x^2-36x+81 ?

The solutions to the equation 0=3x^2-36x+81 are x=9,x=3

Find the zeros of 0=3x^2-36x+81

The zeros of 0=3x^2-36x+81 are x=9,x=3

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0 = 3 x^{2} - 36 x + 81

x = 9, x = 3

Solution steps

0 = 3 x^{2} - 36 x + 81

Switch sides

3 x^{2} - 36 x + 81 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 3 \cdot 81}{2 \cdot 3}

(- 36)^{2} - 4 \cdot 3 \cdot 81 = 18

x_{1, 2} = \frac{- ( - 36 ) \pm 18}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 18}{2 \cdot 3}, x_{2} = \frac{- ( - 36 ) - 18}{2 \cdot 3}

x = \frac{- ( - 36 ) + 18}{2 \cdot 3} : 9

x = \frac{- ( - 36 ) - 18}{2 \cdot 3} : 3

The solutions to the quadratic equation are:

x = 9, x = 3

2 n^{2} + 2 n - 84 = 0

b^{2} + 6 b - 7 = 0

6 x^{2} + 23 x = 13

2 x^{2} + 10 x - 132 = 0

4 s^{2} + 9 = 12 s

What are the solutions to the equation 0=3x^2-36x+81 ?
The solutions to the equation 0=3x^2-36x+81 are x=9,x=3
Find the zeros of 0=3x^2-36x+81
The zeros of 0=3x^2-36x+81 are x=9,x=3