What are the solutions to the equation 6x^2+23x=13 ?

The solutions to the equation 6x^2+23x=13 are x= 1/2 ,x=-13/3

Find the zeros of 6x^2+23x=13

The zeros of 6x^2+23x=13 are x= 1/2 ,x=-13/3

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6 x^{2} + 23 x = 13

x = \frac{1}{2}, x = - \frac{13}{3}

Decimal Notation

x = 0.5, x = - 4.33333 \dots

Solution steps

6 x^{2} + 23 x = 13

Move

13

to the left side

6 x^{2} + 23 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 23 \pm 2 3 ^{2} - 4 \cdot 6 ( - 13 )}{2 \cdot 6}

2 3^{2} - 4 \cdot 6 (- 13) = 29

x_{1, 2} = \frac{- 23 \pm 29}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 23 + 29}{2 \cdot 6}, x_{2} = \frac{- 23 - 29}{2 \cdot 6}

x = \frac{- 23 + 29}{2 \cdot 6} : \frac{1}{2}

x = \frac{- 23 - 29}{2 \cdot 6} : - \frac{13}{3}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{13}{3}

2 x^{2} + 10 x - 132 = 0

4 s^{2} + 9 = 12 s

x^{2} - 2 x + 11 = 5

\frac{x ^{2} - x}{- 1} = - 3

6 x^{2} + x - 35 = 0

What are the solutions to the equation 6x^2+23x=13 ?
The solutions to the equation 6x^2+23x=13 are x= 1/2 ,x=-13/3
Find the zeros of 6x^2+23x=13
The zeros of 6x^2+23x=13 are x= 1/2 ,x=-13/3