What is factor 4v^2+12v+9 ?

The solution to factor 4v^2+12v+9 is (2v+3)^2

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factor 4v^2+12v+9

factor

4 v^{2} + 12 v + 9

(2 v + 3)^{2}

Solution steps

4 v^{2} + 12 v + 9

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

4 v^{2} = (2 v)^{2}

9 = 3^{2}

12 v = 2 \cdot 2 v \cdot 3

= (2 v)^{2} + 2 \cdot 2 v \cdot 3 + 3^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

(2 v)^{2} + 2 \cdot 2 v \cdot 3 + 3^{2} = (2 v + 3)^{2}

= (2 v + 3)^{2}

(\frac{( 3 x y ^{- 5} ) ^{3}}{( x ^{- 2} y ^{2} ) ^{- 4}})^{- 2}

- 11 \cdot - 11

x - \frac{2 - x}{3} = - \frac{x + 1}{3} + \frac{3}{2}

∣ 2 (x - 1) + 8 ∣ \leq 26

(6 y)^{3}