What are the solutions to the equation 6x^2+x-35=0 ?

The solutions to the equation 6x^2+x-35=0 are x= 7/3 ,x=-5/2

Find the zeros of 6x^2+x-35=0

The zeros of 6x^2+x-35=0 are x= 7/3 ,x=-5/2

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6 x^{2} + x - 35 = 0

x = \frac{7}{3}, x = - \frac{5}{2}

Decimal Notation

x = 2.33333 \dots, x = - 2.5

Solution steps

6 x^{2} + x - 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 6 ( - 35 )}{2 \cdot 6}

1^{2} - 4 \cdot 6 (- 35) = 29

x_{1, 2} = \frac{- 1 \pm 29}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 1 + 29}{2 \cdot 6}, x_{2} = \frac{- 1 - 29}{2 \cdot 6}

x = \frac{- 1 + 29}{2 \cdot 6} : \frac{7}{3}

x = \frac{- 1 - 29}{2 \cdot 6} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = \frac{7}{3}, x = - \frac{5}{2}

4 b^{2} - 4 b + 7 = 66

r, 0.0119 = \frac{1}{2} (326) r^{2}

6.28 (\frac{4 - x}{2})^{2} = 20.12

(x - 4) (x - 10) = 0

2 x^{2} - 6 = x^{2} + 7 x - 9

What are the solutions to the equation 6x^2+x-35=0 ?
The solutions to the equation 6x^2+x-35=0 are x= 7/3 ,x=-5/2
Find the zeros of 6x^2+x-35=0
The zeros of 6x^2+x-35=0 are x= 7/3 ,x=-5/2