What are the solutions to the equation x^2+20x-20=0 ?

The solutions to the equation x^2+20x-20=0 are x=2(sqrt(30)-5),x=-2(5+sqrt(30))

Find the zeros of x^2+20x-20=0

The zeros of x^2+20x-20=0 are x=2(sqrt(30)-5),x=-2(5+sqrt(30))

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x^{2} + 20 x - 20 = 0

x = 2 (30 - 5), x = - 2 (5 + 30)

Decimal Notation

x = 0.95445 \dots, x = - 20.95445 \dots

Solution steps

x^{2} + 20 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot (- 20) = 430

x_{1, 2} = \frac{- 20 \pm 4 30}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 4 30}{2 \cdot 1}, x_{2} = \frac{- 20 - 4 30}{2 \cdot 1}

x = \frac{- 20 + 4 30}{2 \cdot 1} : 2 (30 - 5)

x = \frac{- 20 - 4 30}{2 \cdot 1} : - 2 (5 + 30)

The solutions to the quadratic equation are:

x = 2 (30 - 5), x = - 2 (5 + 30)

b^{2} - 18 b - 24 = 9 - 4 b

x (x - 17) = - 60

6 x^{2} + 19 x = 20

46.39 = 46.8 + 30.2 t - 4.9 t^{2}

6 (x + 2)^{2} + 7 (x + 2) - 3 = 0

What are the solutions to the equation x^2+20x-20=0 ?
The solutions to the equation x^2+20x-20=0 are x=2(sqrt(30)-5),x=-2(5+sqrt(30))
Find the zeros of x^2+20x-20=0
The zeros of x^2+20x-20=0 are x=2(sqrt(30)-5),x=-2(5+sqrt(30))