What are the solutions to the equation x^2+18x=7 ?

The solutions to the equation x^2+18x=7 are x=-9+2sqrt(22),x=-9-2sqrt(22)

Find the zeros of x^2+18x=7

The zeros of x^2+18x=7 are x=-9+2sqrt(22),x=-9-2sqrt(22)

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x^{2} + 18 x = 7

x = - 9 + 222, x = - 9 - 222

Decimal Notation

x = 0.38083 \dots, x = - 18.38083 \dots

Solution steps

x^{2} + 18 x = 7

Move

7

to the left side

x^{2} + 18 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot (- 7) = 422

x_{1, 2} = \frac{- 18 \pm 4 22}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 4 22}{2 \cdot 1}, x_{2} = \frac{- 18 - 4 22}{2 \cdot 1}

x = \frac{- 18 + 4 22}{2 \cdot 1} : - 9 + 222

x = \frac{- 18 - 4 22}{2 \cdot 1} : - 9 - 222

The solutions to the quadratic equation are:

x = - 9 + 222, x = - 9 - 222

x^{2} - 14 x - 12 = 4

m^{2} + 12 = 0

x^{2} + 3 x + 8

x, f = 4 x^{2} - 4 x y + y^{2}

x^{2} + 3 x - 7

What are the solutions to the equation x^2+18x=7 ?
The solutions to the equation x^2+18x=7 are x=-9+2sqrt(22),x=-9-2sqrt(22)
Find the zeros of x^2+18x=7
The zeros of x^2+18x=7 are x=-9+2sqrt(22),x=-9-2sqrt(22)