What are the solutions to the equation 3x^2-24x+100=73 ?

The solutions to the equation 3x^2-24x+100=73 are x=4+sqrt(7),x=4-sqrt(7)

Find the zeros of 3x^2-24x+100=73

The zeros of 3x^2-24x+100=73 are x=4+sqrt(7),x=4-sqrt(7)

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3 x^{2} - 24 x + 100 = 73

x = 4 + 7, x = 4 - 7

Decimal Notation

x = 6.64575 \dots, x = 1.35424 \dots

Solution steps

3 x^{2} - 24 x + 100 = 73

Move

73

to the left side

3 x^{2} - 24 x + 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 3 \cdot 27}{2 \cdot 3}

(- 24)^{2} - 4 \cdot 3 \cdot 27 = 67

x_{1, 2} = \frac{- ( - 24 ) \pm 6 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 6 7}{2 \cdot 3}, x_{2} = \frac{- ( - 24 ) - 6 7}{2 \cdot 3}

x = \frac{- ( - 24 ) + 6 7}{2 \cdot 3} : 4 + 7

x = \frac{- ( - 24 ) - 6 7}{2 \cdot 3} : 4 - 7

The solutions to the quadratic equation are:

x = 4 + 7, x = 4 - 7

7 x^{2} + 9 x - j = 0

- 4 x^{2} - 6 x + 2 = 0

1 x + 4 - x^{2} - x = x + 10 x^{2} + 2 x - 8

b, M = a + \frac{b ^{2}}{c}

4 - x^{2} = 4 - 2 x

What are the solutions to the equation 3x^2-24x+100=73 ?
The solutions to the equation 3x^2-24x+100=73 are x=4+sqrt(7),x=4-sqrt(7)
Find the zeros of 3x^2-24x+100=73
The zeros of 3x^2-24x+100=73 are x=4+sqrt(7),x=4-sqrt(7)