What are the solutions to the equation -4x^2-6x+2=0 ?

The solutions to the equation -4x^2-6x+2=0 are x=-(3+sqrt(17))/4 ,x=(sqrt(17)-3)/4

Find the zeros of -4x^2-6x+2=0

The zeros of -4x^2-6x+2=0 are x=-(3+sqrt(17))/4 ,x=(sqrt(17)-3)/4

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- 4 x^{2} - 6 x + 2 = 0

x = - \frac{3 + 17}{4}, x = \frac{17 - 3}{4}

Decimal Notation

x = - 1.78077 \dots, x = 0.28077 \dots

Solution steps

- 4 x^{2} - 6 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 4 ) \cdot 2}{2 ( - 4 )}

(- 6)^{2} - 4 (- 4) \cdot 2 = 217

x_{1, 2} = \frac{- ( - 6 ) \pm 2 17}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 17}{2 ( - 4 )}, x_{2} = \frac{- ( - 6 ) - 2 17}{2 ( - 4 )}

x = \frac{- ( - 6 ) + 2 17}{2 ( - 4 )} : - \frac{3 + 17}{4}

x = \frac{- ( - 6 ) - 2 17}{2 ( - 4 )} : \frac{17 - 3}{4}

The solutions to the quadratic equation are:

x = - \frac{3 + 17}{4}, x = \frac{17 - 3}{4}

1 x + 4 - x^{2} - x = x + 10 x^{2} + 2 x - 8

b, M = a + \frac{b ^{2}}{c}

4 - x^{2} = 4 - 2 x

a = 3.14 r^{2}

p^{2} - 14 p + 49 = 0

What are the solutions to the equation -4x^2-6x+2=0 ?
The solutions to the equation -4x^2-6x+2=0 are x=-(3+sqrt(17))/4 ,x=(sqrt(17)-3)/4
Find the zeros of -4x^2-6x+2=0
The zeros of -4x^2-6x+2=0 are x=-(3+sqrt(17))/4 ,x=(sqrt(17)-3)/4