What are the solutions to the equation 5(x+2)^2+125=0 ?

The solutions to the equation 5(x+2)^2+125=0 are x=5i-2,x=-5i-2

Find the zeros of 5(x+2)^2+125=0

The zeros of 5(x+2)^2+125=0 are x=5i-2,x=-5i-2

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5 (x + 2)^{2} + 125 = 0

x = 5 i - 2, x = - 5 i - 2

Solution steps

5 (x + 2)^{2} + 125 = 0

Move

125

to the right side

5 (x + 2)^{2} = - 125

Divide both sides by

5

(x + 2)^{2} = - 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = - 25 : x = 5 i - 2

Solve

x + 2 = - - 25 : x = - 5 i - 2

The solutions to the quadratic equation are:

x = 5 i - 2, x = - 5 i - 2

11 x^{2} = - 121 x

x^{2} - 5 x + 5 = 0

x, x - x^{2} - x y = 0

2 x^{2} = - x - 1

- 4 y^{2} - 8 y = 0

What are the solutions to the equation 5(x+2)^2+125=0 ?
The solutions to the equation 5(x+2)^2+125=0 are x=5i-2,x=-5i-2
Find the zeros of 5(x+2)^2+125=0
The zeros of 5(x+2)^2+125=0 are x=5i-2,x=-5i-2