What are the solutions to the equation 8x^2+18x-24=0 ?

The solutions to the equation 8x^2+18x-24=0 are x=(-9+sqrt(273))/8 ,x=-(9+sqrt(273))/8

Find the zeros of 8x^2+18x-24=0

The zeros of 8x^2+18x-24=0 are x=(-9+sqrt(273))/8 ,x=-(9+sqrt(273))/8

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8 x^{2} + 18 x - 24 = 0

x = \frac{- 9 + 273}{8}, x = - \frac{9 + 273}{8}

Decimal Notation

x = 0.94033 \dots, x = - 3.19033 \dots

Solution steps

8 x^{2} + 18 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 8 ( - 24 )}{2 \cdot 8}

1 8^{2} - 4 \cdot 8 (- 24) = 2273

x_{1, 2} = \frac{- 18 \pm 2 273}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 18 + 2 273}{2 \cdot 8}, x_{2} = \frac{- 18 - 2 273}{2 \cdot 8}

x = \frac{- 18 + 2 273}{2 \cdot 8} : \frac{- 9 + 273}{8}

x = \frac{- 18 - 2 273}{2 \cdot 8} : - \frac{9 + 273}{8}

The solutions to the quadratic equation are:

x = \frac{- 9 + 273}{8}, x = - \frac{9 + 273}{8}

6 r^{2} - 7 r + 2 = 0

8 (6 - x) - 3 x (6 - x) = 0

y, y^{2} - x^{2} y + 3 x^{3} = 4

x^{2} + 2 x - 7 = 0

y, x^{2} y^{2} - 3 x + y = 4

What are the solutions to the equation 8x^2+18x-24=0 ?
The solutions to the equation 8x^2+18x-24=0 are x=(-9+sqrt(273))/8 ,x=-(9+sqrt(273))/8
Find the zeros of 8x^2+18x-24=0
The zeros of 8x^2+18x-24=0 are x=(-9+sqrt(273))/8 ,x=-(9+sqrt(273))/8