What are the solutions to the equation 8(6-x)-3x(6-x)=0 ?

The solutions to the equation 8(6-x)-3x(6-x)=0 are x=6,x= 8/3

Find the zeros of 8(6-x)-3x(6-x)=0

The zeros of 8(6-x)-3x(6-x)=0 are x=6,x= 8/3

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8 (6 - x) - 3 x (6 - x) = 0

x = 6, x = \frac{8}{3}

Decimal Notation

x = 6, x = 2.66666 \dots

Solution steps

8 (6 - x) - 3 x (6 - x) = 0

Expand

8 (6 - x) - 3 x (6 - x) : 48 - 26 x + 3 x^{2}

48 - 26 x + 3 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} - 26 x + 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 3 \cdot 48}{2 \cdot 3}

(- 26)^{2} - 4 \cdot 3 \cdot 48 = 10

x_{1, 2} = \frac{- ( - 26 ) \pm 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 26 ) + 10}{2 \cdot 3}, x_{2} = \frac{- ( - 26 ) - 10}{2 \cdot 3}

x = \frac{- ( - 26 ) + 10}{2 \cdot 3} : 6

x = \frac{- ( - 26 ) - 10}{2 \cdot 3} : \frac{8}{3}

The solutions to the quadratic equation are:

x = 6, x = \frac{8}{3}

y, y^{2} - x^{2} y + 3 x^{3} = 4

x^{2} + 2 x - 7 = 0

y, x^{2} y^{2} - 3 x + y = 4

2 x^{2} - 4 x + 4 = 34

- 4 x^{2} - 4 x + 5 = - 7 x^{2}

What are the solutions to the equation 8(6-x)-3x(6-x)=0 ?
The solutions to the equation 8(6-x)-3x(6-x)=0 are x=6,x= 8/3
Find the zeros of 8(6-x)-3x(6-x)=0
The zeros of 8(6-x)-3x(6-x)=0 are x=6,x= 8/3