What are the solutions to the equation t^2+4t-33=0 ?

The solutions to the equation t^2+4t-33=0 are t=-2+sqrt(37),t=-2-sqrt(37)

Find the zeros of t^2+4t-33=0

The zeros of t^2+4t-33=0 are t=-2+sqrt(37),t=-2-sqrt(37)

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t^{2} + 4 t - 33 = 0

t = - 2 + 37, t = - 2 - 37

Decimal Notation

t = 4.08276 \dots, t = - 8.08276 \dots

Solution steps

t^{2} + 4 t - 33 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 33 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 33) = 237

t_{1, 2} = \frac{- 4 \pm 2 37}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- 4 + 2 37}{2 \cdot 1}, t_{2} = \frac{- 4 - 2 37}{2 \cdot 1}

t = \frac{- 4 + 2 37}{2 \cdot 1} : - 2 + 37

t = \frac{- 4 - 2 37}{2 \cdot 1} : - 2 - 37

The solutions to the quadratic equation are:

t = - 2 + 37, t = - 2 - 37

0 = - \frac{1}{16} (x - 32)^{2} + 67

x^{2} - 8 x - 9 = 0

x^{3} + x^{2} + 4 x + 4

\frac{x}{3} = \frac{5}{8}

- 7 x + 1 \geq 22 or - 10 x + 41 \geq 81

What are the solutions to the equation t^2+4t-33=0 ?
The solutions to the equation t^2+4t-33=0 are t=-2+sqrt(37),t=-2-sqrt(37)
Find the zeros of t^2+4t-33=0
The zeros of t^2+4t-33=0 are t=-2+sqrt(37),t=-2-sqrt(37)