What are the solutions to the equation x^2(-2)=16 ?

The solutions to the equation x^2(-2)=16 are x=2sqrt(2)i,x=-2sqrt(2)i

Find the zeros of x^2(-2)=16

The zeros of x^2(-2)=16 are x=2sqrt(2)i,x=-2sqrt(2)i

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x^{2} (- 2) = 16

x = 22 i, x = - 22 i

Solution steps

x^{2} (- 2) = 16

Divide both sides by

- 2

x^{2} = - 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 8, x = - - 8

- 8 = 22 i

- - 8 = - 22 i

x = 22 i, x = - 22 i

x^{2} + x + 32 = 0

y, (x + y)^{2} = x

r^{2} - 8 r - 22 = 6

78 = π r^{2} (\frac{101}{360})

20 = 0.9 v - 0.01 v^{2}

What are the solutions to the equation x^2(-2)=16 ?
The solutions to the equation x^2(-2)=16 are x=2sqrt(2)i,x=-2sqrt(2)i
Find the zeros of x^2(-2)=16
The zeros of x^2(-2)=16 are x=2sqrt(2)i,x=-2sqrt(2)i