What are the solutions to the equation 2x^2+2x+24=0 ?

The solutions to the equation 2x^2+2x+24=0 are x=-1/2+i(sqrt(47))/2 ,x=-1/2-i(sqrt(47))/2

Find the zeros of 2x^2+2x+24=0

The zeros of 2x^2+2x+24=0 are x=-1/2+i(sqrt(47))/2 ,x=-1/2-i(sqrt(47))/2

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2 x^{2} + 2 x + 24 = 0

x = - \frac{1}{2} + i \frac{47}{2}, x = - \frac{1}{2} - i \frac{47}{2}

Solution steps

2 x^{2} + 2 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 \cdot 24}{2 \cdot 2}

Simplify

2^{2} - 4 \cdot 2 \cdot 24 : 247 i

x_{1, 2} = \frac{- 2 \pm 2 47 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 2 + 2 47 i}{2 \cdot 2}, x_{2} = \frac{- 2 - 2 47 i}{2 \cdot 2}

x = \frac{- 2 + 2 47 i}{2 \cdot 2} : - \frac{1}{2} + i \frac{47}{2}

x = \frac{- 2 - 2 47 i}{2 \cdot 2} : - \frac{1}{2} - i \frac{47}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{47}{2}, x = - \frac{1}{2} - i \frac{47}{2}

x + 9 = \frac{( x - 11 ) ^{2}}{2}

x^{2} - 5 x - 34 = 0

2 x^{2} + 4 x + 1 = 3 x - 2

5 x^{2} = - 2

5 x^{2} = - x

What are the solutions to the equation 2x^2+2x+24=0 ?
The solutions to the equation 2x^2+2x+24=0 are x=-1/2+i(sqrt(47))/2 ,x=-1/2-i(sqrt(47))/2
Find the zeros of 2x^2+2x+24=0
The zeros of 2x^2+2x+24=0 are x=-1/2+i(sqrt(47))/2 ,x=-1/2-i(sqrt(47))/2