What are the solutions to the equation 18p^2-164p+285=-3-8p ?

The solutions to the equation 18p^2-164p+285=-3-8p are p=6,p= 8/3

Find the zeros of 18p^2-164p+285=-3-8p

The zeros of 18p^2-164p+285=-3-8p are p=6,p= 8/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

18 p^{2} - 164 p + 285 = - 3 - 8 p

p = 6, p = \frac{8}{3}

Decimal Notation

p = 6, p = 2.66666 \dots

Solution steps

18 p^{2} - 164 p + 285 = - 3 - 8 p

Move

8 p

to the left side

18 p^{2} - 156 p + 285 = - 3

Move

3

to the left side

18 p^{2} - 156 p + 288 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 156 ) \pm ( - 156 ) ^{2} - 4 \cdot 18 \cdot 288}{2 \cdot 18}

(- 156)^{2} - 4 \cdot 18 \cdot 288 = 60

p_{1, 2} = \frac{- ( - 156 ) \pm 60}{2 \cdot 18}

Separate the solutions

p_{1} = \frac{- ( - 156 ) + 60}{2 \cdot 18}, p_{2} = \frac{- ( - 156 ) - 60}{2 \cdot 18}

p = \frac{- ( - 156 ) + 60}{2 \cdot 18} : 6

p = \frac{- ( - 156 ) - 60}{2 \cdot 18} : \frac{8}{3}

The solutions to the quadratic equation are:

p = 6, p = \frac{8}{3}

10 m^{2} - 2 m = 7

3 (x + 4)^{2} - 5 = 55

x, y = x^{2} - 4

x, y = x^{2} - 6

x^{2} + 6 x - 10 = 0

What are the solutions to the equation 18p^2-164p+285=-3-8p ?
The solutions to the equation 18p^2-164p+285=-3-8p are p=6,p= 8/3
Find the zeros of 18p^2-164p+285=-3-8p
The zeros of 18p^2-164p+285=-3-8p are p=6,p= 8/3