What are the solutions to the equation solvefor x,y=x^2-4 ?

The solutions to the equation solvefor x,y=x^2-4 are x=sqrt(y+4),x=-sqrt(y+4)

Find the zeros of solvefor x,y=x^2-4

The zeros of solvefor x,y=x^2-4 are x=sqrt(y+4),x=-sqrt(y+4)

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solve for

x, y = x^{2} - 4

x = y + 4, x = - y + 4

Solution steps

y = x^{2} - 4

Switch sides

x^{2} - 4 = y

Move

4

to the right side

x^{2} = y + 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = y + 4, x = - y + 4

x, y = x^{2} - 6

x^{2} + 6 x - 10 = 0

(s - 2)^{2} = 0

x^{2} - x = 2 x^{2} - 1

f (- 3) = (x - 2)^{2}, x < - 1

What are the solutions to the equation solvefor x,y=x^2-4 ?
The solutions to the equation solvefor x,y=x^2-4 are x=sqrt(y+4),x=-sqrt(y+4)
Find the zeros of solvefor x,y=x^2-4
The zeros of solvefor x,y=x^2-4 are x=sqrt(y+4),x=-sqrt(y+4)