What are the solutions to the equation f(-3)=(x-2)^2,x<-1 ?

The solutions to the equation f(-3)=(x-2)^2,x<-1 are x=sqrt(f(-3))+2,x=-sqrt(f(-3))+2

Find the zeros of f(-3)=(x-2)^2,x<-1

The zeros of f(-3)=(x-2)^2,x<-1 are x=sqrt(f(-3))+2,x=-sqrt(f(-3))+2

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The solutions to the equation f(-3)=(x-2)^2,x<-1 are x=sqrt(f(-3))+2,x=-sqrt(f(-3))+2

The zeros of f(-3)=(x-2)^2,x<-1 are x=sqrt(f(-3))+2,x=-sqrt(f(-3))+2

f (- 3) = (x - 2)^{2}, x < - 1

x = f (- 3) + 2, x = - f (- 3) + 2

Solution steps

f (- 3) = (x - 2)^{2}, x < - 1

Switch sides

(x - 2)^{2} = f (- 3)

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = f (- 3) : x = f (- 3) + 2

Solve

x - 2 = - f (- 3) : x = - f (- 3) + 2

The solutions to the quadratic equation are:

x = f (- 3) + 2, x = - f (- 3) + 2

- x^{2} - x - 20 = 0

x^{2} - 28 x = 45

90 x - 135 - 2 x^{2} + 3 x = 45 x

n^{2} - n - 1 = 0

7 m^{2} + 2 m - 4 = 0

What are the solutions to the equation f(-3)=(x-2)^2,x<-1 ?
The solutions to the equation f(-3)=(x-2)^2,x<-1 are x=sqrt(f(-3))+2,x=-sqrt(f(-3))+2
Find the zeros of f(-3)=(x-2)^2,x<-1
The zeros of f(-3)=(x-2)^2,x<-1 are x=sqrt(f(-3))+2,x=-sqrt(f(-3))+2