What are the solutions to the equation -x^2-x-20=0 ?

The solutions to the equation -x^2-x-20=0 are x=-1/2-i(sqrt(79))/2 ,x=-1/2+i(sqrt(79))/2

Find the zeros of -x^2-x-20=0

The zeros of -x^2-x-20=0 are x=-1/2-i(sqrt(79))/2 ,x=-1/2+i(sqrt(79))/2

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- x^{2} - x - 20 = 0

x = - \frac{1}{2} - i \frac{79}{2}, x = - \frac{1}{2} + i \frac{79}{2}

Solution steps

- x^{2} - x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 1 ) ( - 20 )}{2 ( - 1 )}

Simplify

(- 1)^{2} - 4 (- 1) (- 20) : 79 i

x_{1, 2} = \frac{- ( - 1 ) \pm 79 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 79 i}{2 ( - 1 )}, x_{2} = \frac{- ( - 1 ) - 79 i}{2 ( - 1 )}

x = \frac{- ( - 1 ) + 79 i}{2 ( - 1 )} : - \frac{1}{2} - i \frac{79}{2}

x = \frac{- ( - 1 ) - 79 i}{2 ( - 1 )} : - \frac{1}{2} + i \frac{79}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} - i \frac{79}{2}, x = - \frac{1}{2} + i \frac{79}{2}

x^{2} - 28 x = 45

90 x - 135 - 2 x^{2} + 3 x = 45 x

n^{2} - n - 1 = 0

7 m^{2} + 2 m - 4 = 0

h, (7 - h)^{2} + (2 - k)^{2} = 0

What are the solutions to the equation -x^2-x-20=0 ?
The solutions to the equation -x^2-x-20=0 are x=-1/2-i(sqrt(79))/2 ,x=-1/2+i(sqrt(79))/2
Find the zeros of -x^2-x-20=0
The zeros of -x^2-x-20=0 are x=-1/2-i(sqrt(79))/2 ,x=-1/2+i(sqrt(79))/2