What are the solutions to the equation y^2+4y+6=0 ?

The solutions to the equation y^2+4y+6=0 are y=-2+sqrt(2)i,y=-2-sqrt(2)i

Find the zeros of y^2+4y+6=0

The zeros of y^2+4y+6=0 are y=-2+sqrt(2)i,y=-2-sqrt(2)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{2} + 4 y + 6 = 0

y = - 2 + 2 i, y = - 2 - 2 i

Solution steps

y^{2} + 4 y + 6 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 6 : 22 i

y_{1, 2} = \frac{- 4 \pm 2 2 i}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 4 + 2 2 i}{2 \cdot 1}, y_{2} = \frac{- 4 - 2 2 i}{2 \cdot 1}

y = \frac{- 4 + 2 2 i}{2 \cdot 1} : - 2 + 2 i

y = \frac{- 4 - 2 2 i}{2 \cdot 1} : - 2 - 2 i

The solutions to the quadratic equation are:

y = - 2 + 2 i, y = - 2 - 2 i

2 (x - 3)^{2} = 18

3 g^{2} + 4 g - 9 = 0

x, z = - 4 x^{2} - 6 x y - 3 y^{2} + 2 x + y + 10

(x - 3)^{2} + 6 = - 30

x^{2} - 7 x - 98 = 0

What are the solutions to the equation y^2+4y+6=0 ?
The solutions to the equation y^2+4y+6=0 are y=-2+sqrt(2)i,y=-2-sqrt(2)i
Find the zeros of y^2+4y+6=0
The zeros of y^2+4y+6=0 are y=-2+sqrt(2)i,y=-2-sqrt(2)i