What are the solutions to the equation 7x^2+25x=12 ?

The solutions to the equation 7x^2+25x=12 are x= 3/7 ,x=-4

Find the zeros of 7x^2+25x=12

The zeros of 7x^2+25x=12 are x= 3/7 ,x=-4

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7 x^{2} + 25 x = 12

x = \frac{3}{7}, x = - 4

Decimal

x = 0.42857 \dots, x = - 4

Solution steps

7 x^{2} + 25 x = 12

Move

12

to the left side

7 x^{2} + 25 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 25 \pm 2 5 ^{2} - 4 \cdot 7 ( - 12 )}{2 \cdot 7}

2 5^{2} - 4 \cdot 7 (- 12) = 31

x_{1, 2} = \frac{- 25 \pm 31}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 25 + 31}{2 \cdot 7}, x_{2} = \frac{- 25 - 31}{2 \cdot 7}

x = \frac{- 25 + 31}{2 \cdot 7} : \frac{3}{7}

x = \frac{- 25 - 31}{2 \cdot 7} : - 4

The solutions to the quadratic equation are:

x = \frac{3}{7}, x = - 4

x^{2} - 3 x = 108

400 - 16 x^{2} = 0

k^{2} - 4 k + 4 = 0

x, - x^{2} + \frac{9 y ^{2}}{4} = 0

10 + 3 x = x^{2}

What are the solutions to the equation 7x^2+25x=12 ?
The solutions to the equation 7x^2+25x=12 are x= 3/7 ,x=-4
Find the zeros of 7x^2+25x=12
The zeros of 7x^2+25x=12 are x= 3/7 ,x=-4