What are the solutions to the equation (5-x)(-1-x)+8=0 ?

The solutions to the equation (5-x)(-1-x)+8=0 are x=3,x=1

Find the zeros of (5-x)(-1-x)+8=0

The zeros of (5-x)(-1-x)+8=0 are x=3,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(5 - x) (- 1 - x) + 8 = 0

x = 3, x = 1

Solution steps

(5 - x) (- 1 - x) + 8 = 0

Expand

(5 - x) (- 1 - x) + 8 : x^{2} - 4 x + 3

x^{2} - 4 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 3 = 2

x_{1, 2} = \frac{- ( - 4 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2}{2 \cdot 1} : 3

x = \frac{- ( - 4 ) - 2}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 3, x = 1

12 t + 9 = 5 t^{2}

2 x^{2} + 20 x + 51 = 0

x = (6 - x)^{2}

- x^{2} - 5 x + 14 = 0

4 n^{2} + 3 n = 3

What are the solutions to the equation (5-x)(-1-x)+8=0 ?
The solutions to the equation (5-x)(-1-x)+8=0 are x=3,x=1
Find the zeros of (5-x)(-1-x)+8=0
The zeros of (5-x)(-1-x)+8=0 are x=3,x=1