What are the solutions to the equation 0=-3x^2+30x-72 ?

The solutions to the equation 0=-3x^2+30x-72 are x=4,x=6

Find the zeros of 0=-3x^2+30x-72

The zeros of 0=-3x^2+30x-72 are x=4,x=6

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0 = - 3 x^{2} + 30 x - 72

x = 4, x = 6

Solution steps

0 = - 3 x^{2} + 30 x - 72

Switch sides

- 3 x^{2} + 30 x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 30 \pm 3 0 ^{2} - 4 ( - 3 ) ( - 72 )}{2 ( - 3 )}

3 0^{2} - 4 (- 3) (- 72) = 6

x_{1, 2} = \frac{- 30 \pm 6}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 30 + 6}{2 ( - 3 )}, x_{2} = \frac{- 30 - 6}{2 ( - 3 )}

x = \frac{- 30 + 6}{2 ( - 3 )} : 4

x = \frac{- 30 - 6}{2 ( - 3 )} : 6

The solutions to the quadratic equation are:

x = 4, x = 6

2 x^{2} + 8 x = - 9

a x^{2} + 3 x - 6 = 0

- 6 x^{2} - 4 x = - 9

m^{2} + 80 m + 1200 = 0

x, x^{2} - 6 x + 13 = 0

What are the solutions to the equation 0=-3x^2+30x-72 ?
The solutions to the equation 0=-3x^2+30x-72 are x=4,x=6
Find the zeros of 0=-3x^2+30x-72
The zeros of 0=-3x^2+30x-72 are x=4,x=6